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Language in C Interview Questions and Answers

Ques. Why doesn't the following code give the desired result?

int x = 3000, y = 2000 ;
long int z = x * y ;
Ans. Here the multiplication is carried out between two ints x and y, and the result that would overflow would be truncated before being assigned to the variable z of type long int. However, to get the correct output, we should use an explicit cast to force long arithmetic as shown below:

long int z = ( long int ) x * y ;
Note that ( long int )( x * y ) would not give the desired effect.

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