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Python Interview Questions and Answers

Ques. How do I use strings to call functions/methods?
Ans. There are various techniques.
* The best is to use a dictionary that maps strings to functions. The primary advantage of this technique is that the strings do not need to match the names of the functions. This is also the primary technique used to emulate a case construct:
def a():
pass
def b():
pass
dispatch = {\\\\\\\\\\\\\\\'go\\\\\\\\\\\\\\\': a, \\\\\\\\\\\\\\\'stop\\\\\\\\\\\\\\\': b} # Note lack of parens for funcs
dispatch[get_input()]() # Note trailing parens to call function
*
Use the built-in function getattr():
import foo
getattr(foo, \\\\\\\\\\\\\\\'bar\\\\\\\\\\\\\\\')()
Note that getattr() works on any object, including classes, class instances, modules, and so on. This is used in several places in the standard library, like this:
class Foo:
def do_foo(self):
def do_bar(self):
f = getattr(foo_instance, \\\\\\\\\\\\\\\'do_\\\\\\\\\\\\\\\' + opname)
f()
* Use locals() or eval() to resolve the function name:
def myFunc():
print \\\\\\\\\\\\\\\"hello\\\\\\\\\\\\\\\"
fname = \\\\\\\\\\\\\\\"myFunc\\\\\\\\\\\\\\\"
f = locals()[fname]
f()
f = eval(fname)
f()
Note: Using eval() is slow and dangerous. If you don\\\\\\\\\\\\\\\'t have absolute control over the contents of the string, someone could pass a string that resulted in an arbitrary function being executed.
Is there an equivalent to Perl\\\\\\\\\\\\\\\'s chomp() for removing trailing newlines from strings?
Starting with Python 2.2, you can use S.rstrip(\\\\\\\\\\\\\\\"\\\\\\\\\\\\\\\\r\\\\\\\\\\\\\\\\n\\\\\\\\\\\\\\\") to remove all occurences of any line terminator
from the end of the string S without removing other trailing whitespace. If the string S represents more
than one line, with several empty lines at the end, the line terminators for all the blank lines will be
removed:
>>> lines = (\\\\\\\\\\\\\\\"line 1 \\\\\\\\\\\\\\\\r\\\\\\\\\\\\\\\\n\\\\\\\\\\\\\\\"
... \\\\\\\\\\\\\\\"\\\\\\\\\\\\\\\\r\\\\\\\\\\\\\\\\n\\\\\\\\\\\\\\\"
... \\\\\\\\\\\\\\\"\\\\\\\\\\\\\\\\r\\\\\\\\\\\\\\\\n\\\\\\\\\\\\\\\")
>>> lines.rstrip(\\\\\\\\\\\\\\\"\\\\\\\\\\\\\\\\n\\\\\\\\\\\\\\\\r\\\\\\\\\\\\\\\")
\\\\\\\\\\\\\\\"line 1 \\\\\\\\\\\\\\\"
Since this is typically only desired when reading text one line at a time, using S.rstrip() this way works
well.
For older versions of Python, There are two partial substitutes:
* If you want to remove all trailing whitespace, use the rstrip() method of string objects. This removes all trailing whitespace, not just a single newline.
* Otherwise, if there is only one line in the string S, use S.splitlines()[0].
Is there a scanf() or sscanf() equivalent?
Not as such.
For simple input parsing, the easiest approach is usually to split the line into whitespace-delimited words using the split() method of string objects and then convert decimal strings to numeric values using int() or float(). split() supports an optional \\\\\\\\\\\\\\\"sep\\\\\\\\\\\\\\\" parameter which is useful if the line uses something other than whitespace as a separator.
For more complicated input parsing, regular expressions more powerful than C\\\\\\\\\\\\\\\'s sscanf() and better suited for the task.
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