Language in C 面接の質問と回答
Question: Why doesn't the following code give the desired result?
Answer: Here the multiplication is carried out between two ints x and y, and the result that would overflow would be truncated before being assigned to the variable z of type long int. However, to get the correct output, we should use an explicit cast to force long arithmetic as shown below:long int z = ( long int ) x * y ; Note that ( long int )( x * y ) would not give the desired effect. |
復習用に保存
この項目をブックマークに追加したり、難しい内容としてマークしたり、復習セットに入れたりできます。
役に立ちましたか？ はい いいえ
ユーザー評価で最も役立つ内容:
- What will be the output of the following code?
void main ()
{ int i = 0 , a[3] ;
a[i] = i++;
printf ("%d",a[i]) ;
} - Why doesn't the following code give the desired result?
int x = 3000, y = 2000 ;
long int z = x * y ; - Why doesn't the following statement work?
char str[ ] = "Hello" ;
strcat ( str, '!' ) ; - How do I know how many elements an array can hold?
- How do I compare character data stored at two different memory locations?