Language in C 面接の質問と回答
Question: What's wrong with the following declaration: char* ptr1, ptr2 ; get errors when I try to use ptr2 as a pointer.
Answer: char * applies only to ptr1 and not to ptr2. Hence ptr1 is getting declared as a char pointer, whereas, ptr2 is being declared merely as a char. This can be rectified in two ways :char *ptr1, *ptr2 ; typedef char* CHARPTR ; CHARPTR ptr1, ptr2 ; |
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