PHP 면접 질문과 답변
Question: How come the code <?php print "Contents: $arr[1]"; ?> works, but <?php print "Contents: $arr[1][2]"; ?> doesn't for two-dimensional array of mine? -Answer: Any time you have an array with more than one dimension, complex parsing syntax is required. print "Contents: {$arr[1][2]}" would've worked. |
복습용 저장
이 항목을 북마크하거나, 어렵게 표시하거나, 복습 세트에 넣을 수 있습니다.
도움이 되었나요? 예 아니요
Most helpful rated by users:
- What does a special set of tags <?= and ?> do in PHP?
- What's the difference between include and require? -
- I am trying to assign a variable the value of 0123, but it keeps coming up with a different number, what's the problem?
- How do you define a constant?
- Would I use print "$a dollars" or "{$a} dollars" to print out the amount of dollars in this example?